a compound on
analysis gave Na =14.31%, S= 9.97/ .
H= 6.62.1. 0= 69.54. calculate emprical
and molecular formula of the compound, Molar
of compound is 322
Answers
Explanation:
Element■mass■At.mass■m%/At■Integral
% (g) mass ratio
Na 14.31 23 0.622 2
S 9.97 32 0.311 1
H 6.22 1 6.22 20
O 69.5 16 4.34 14
Empirical formula is therefore Na2SH20O14
empiricalmass=2×23+32+20×1+14×16=322g
Given:
Molecular mass = 322 g
∴ molecular formula =empirical formula=Na2SH20O14
Given that all the hydrogen in the compound is reset in combination with oxygen as water of crystallisation
If water of crystallization are nH2O then, 2n=20 therefore, n=10
Crystallized water is 10H2O remaining atoms are Na2SO4
therefore, the molecule is Na2SO4.10H2O