Question

A compound on analysis gave the
following percentage composition by
mass : H=9.09; O= 36.36; C = 54.55.
Mol mass of compound is 88. Find its
molecular formula.​

Answer 1

Answer:

C4H8O2

Explanation:

empirical formula =C2H4O

mol mass=88

n=2

molecular formula=C4H8O2