A compound on analysis gave the following percentage composition by mass: H=9.09; O=36.36; C=54.55 . Molecular mass of compound is 88. Find it's molecular formula.
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A compound on analysis gave the following percentage composition by weight: hydrogen = 9.09, oxygen = 36.36 carbon = 54.55. Its VD is 44. ... Empirical formula =C2H4O.
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A compound on analysis gave the following percentage composition by weight: hydrogen = 9.09, oxygen = 36.36 carbon = 54.55. Its VD is 44.
Empirical formula =C2H4O.
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