A compound on analysis was found to contain carbon=34.6% , hydrogen=3.85% and oxygen=61.55%. Calculate its empirical formula
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Answer:
Element C:
Percentage : 34.6
Atomic mass : 12
Gram atoms : 34.6÷12=2.88
Molar ratio : 2.88÷2.88=1
simplest whole number ratio : 3
Element H:
Percentage : 3.85
Atomic mass : 1
Gram atoms : 3.85÷1=3.85
Molar ratio : 3.85÷2.88=1.335
simplest whole number ratio : 4
Element O:
Percentage : 61.55
Atomic mass : 16
Gram atoms : 61.55÷16=3.85
Molar ratio : 3.85÷2.88=1.335
simplest whole number ratio : 4
Therefore the simplest whole number ratios of the different elements are: C : H : O :: 3 : 4 : 4 and the empirical formula of the compound=C₃H₄O₄.
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