Question

a compound with a molar mass of 544.0g/mol is made up of 26.5g of carbon, 2.94g of hydrogen 70.6g oxygen. what is it's empirical and molecular formula? ​

Answer 1

Explanation:

C H N

74 8.7 17.3 Percentage

12 1 14 Atomic Mass

6.17 8.70 1.23 Number of Moles

5.01 7.07 1 Simple molar ratio

( ÷ by 1.23)

Hence, C:H:N=5:7:1

Empirical formula of nicotine is C

5

H

7

N