Question

A compound with an empirical formula of c2oh4 and a molar mass of 88 grams per mole. Calculate its molecular formula.

Answer 1

A compound with an empirical formula of C,OH, and a molar mass of 88 grams per mole. What is the molecular formula of this compound? ₂ OH₃ = 44,05 g/mol.

Answer 2

Given: The compound $C_2OH_4$ has a molar mass of 88.

To find: We have to find its molecular formula.

Solution:

The empirical formula of the compound is $C_2OH_4$.

The atomic mass of C is 12.

The atomic mass of Oxygen is 16 and the atomic mass of H is 1.

Thus the empirical mass of $C_2OH_4$ is

$12 \times 2 + 16 + 4 \times 1 \\ = 24 + 16 + 4 \\ = 44$

The empirical mass is 44.

The molar mass is 88.

Thus n value is 88/44=2.

The formula of the compound is $(C_2OH_4)_2=C_4O_2H_8$.

The molecular formula of the compound is $C_4O_2H_8$.