Question

A compound with an empirical formula of C2OH4 and a molar mass of 88 grams per mole.

Answer 1

Answer:

C4O2H8

Explanation:

Find out the original molar mass of the Empirical Formula compared to the 88 grams  per mole.

--> C (2 x 12.01) + O (1 x 16) + H (4 x 1.01) = 88g/mol

      C 24.02 + O 16 + H 4.04 = 88g/mol

Finally you should get ~ 44n = 88g/mol

After this, you divide 44 on both sides to get N = 2

2 is the factor that makes the equation equal the mass given. So just just multiply it to the Empirical Formula.

C2OH4 x 2 = C4O2H8 <-- Molecular Formula