A compound with an empirical formula of CHO2 has a vapour density of 67.5. Find its molecular
formula. [ C = 12, H = 1 O = 16 ]
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Empiricaz formula is CH
2
O
Mass of Empirical formula =12+12+16=30g
Vapour density =
2
Molar mass of compound
∴90=
2
Molar mass
Molar mass of compound =180g
On dividing the
Empirical formula mass
Molecular formula mass
n=
30
180
=6
On multiply each atom of empirical formula by n we get actual molecular formula
C×+H
2
×6+O×6=C
6
H
12
O
6
The molecular formula of compound is C
6
H
12
O
6
with molar mass 180.
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