A compound with empirical formula C2H5O has a V.D of 45. What is the molecular formula of the compound?
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GIVEN:
- V.D = 45
TO FIND:
- Molecular formula of the compound
SOLUTION:
The empirical formula is C2H5O
Emperical weight = 12 x 2 + 1 x 5 + 16 = 45 g
n = Empirical weight / Molecular weight
= 45/45
= 1
Therefore, the emperical formula is C2H5O.
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