Question

. A compound with molar mass 15g was found to contain
39.62% copper and 20.13% sulfur. Suggest molecular
formula for the compound
(Atomic mass :- Cu = 63, S = 32, 0 = 16) (3)​

Answer 1

Explanation:

Given  A compound with molar mass 159 was found to contain  39.62% copper and 20.13% sulfur. Suggest molecular  formula for the compound

(Atomic mass :- Cu = 63, S = 32, 0 = 16)

• According to question percentage of copper + percentage of sulphur
•                               = 39.62 + 20.13
•                                 = 59.75
• Now the compound contains adequate quantity of oxygen so total percent of elements is 100%
• Therefore of oxygen will be 100 – 59.75
•                                                  = 40.25%
• Copper
• Percentage is 39.62,  
• atomic mass is 63,  
• atomic ratio is 39.62 / 63 = 0.63
• so ratio will be 0.63/0.63 = 1
• Sulphur
• Percentage is 20.13
• Atomic mass is 32
• Atomic ratio is 20.13 / 32 = 0.63
• So ratio will be 0.63/0.63 = 1
• Oxygen
• Percentage is 40.25
• Atomic mass is 16
• Atomic ratio is 40.25 / 16 = 2.51
• So ratio will be 2.51/0.63 = 4
• Therefore empirical formula will be CuSO4 (copper sulphate)
• Also molecular weight is 63 + 32 + 16 = 95 + 16 x 4
•                                                             = 95 + 64
•                                                               = 159

Reference link will be

https://brainly.in/question/3200968