A compound with molecular mass 180 is acylated with CH3COCl to get a compound with molecular mass 390. The no. of amino groups present per molecule of former compound is
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Acylation of an amine group is represented as follows:
RNH2 + CH3COCl→RNHCOCH3 + HCl
Mass of product = 390 g
Mass of amine = 180 g
Increase in mass = 390- 180 g = 210 g
mass of one molecule of CH3CO = 12 + 3 + 12 + 16 = 43
Since, one hydrogen atom of NH2 group is replaced mass added per molecule = 43 - 1 = 42 g
So, number of acetyl groups introduced = 210/42 = 5
Thus, number of amino groups in the original compound = 5
RNH2 + CH3COCl→RNHCOCH3 + HCl
Mass of product = 390 g
Mass of amine = 180 g
Increase in mass = 390- 180 g = 210 g
mass of one molecule of CH3CO = 12 + 3 + 12 + 16 = 43
Since, one hydrogen atom of NH2 group is replaced mass added per molecule = 43 - 1 = 42 g
So, number of acetyl groups introduced = 210/42 = 5
Thus, number of amino groups in the original compound = 5
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Answer:
5 amino groups
Explanation:
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