A compound ‘X’ on heating with excess conc. sulphuric acid at 443 K gives an unsaturated compound ‘Y’. ‘X’ also reacts with sodium metal to evolve a colourless gas ‘Z’. Identify ‘X’, ‘Y’ and ‘Z’. Write the equation of the chemical reaction of formation of ‘Y’ and also write the role of sulphuric acid in the reaction
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C2H6 + 7/2O2 -----> 2CO2 + 3H2O
Combustion of ethane gives 2 molecules of CO2 and 3 molecules of H2O. So, Z is ethane.
Z is formed on reduction of Y in the presence of nickel.
C2H4 + H2 -----> C2H6
ethanol with a large quantity of concentrated sulphuric acid on heating produces ethene.
CH3-CH2-OH -------> CH2=CH2 + H2O
Therefore, X is ethanol, Y is ethene and Z is ethane.
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x is c2h5oh
y is ch2=ch2
z is h2
y is ch2=ch2
z is h2
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