A compound x on hydrolysis with a strong base give y and z find x yand z
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Answered by
0
CH3CooNa+NaOH------- CH4+Na2CO3
hence
x=CH3CooNa
y=CH4
z=Na2CO3
hence
x=CH3CooNa
y=CH4
z=Na2CO3
Answered by
0
CH₃COOH + NaOH = CH₃COONa + H₂O
hence
x=CH₃COOH
y=CH₃COONa
z=H₂O
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