Question

A compound X on treating with dilute HCl produces gas Y and sodium chloride and water. 1) Identify X and Y. 2) Write the equation involved. 3) On passing Y through lime water, white precipitate compound Z is produced. Identify Z and write the equation.

Answer 1

Answer:

X-2NA Y-H2gas liberated outside

Explanation:

Then eauation will be 2NA+2HCL=2NÀCL+H2 is balanced equation

WHEN METAL REACTS WITH ACID THEN THEY SALT AND HYDROGEN GAS

Answer 2

Let us complete this equation

Explanation:

A compound X on treating with dilute HCl produces gas Y ,NaCl and water that is :

Na₂CO₃ + HCl---> NaCl + CO₂ +H₂O

1) In this compound X is --> sodium carbonate

                 gas Y is ----> carbon dioxide

2)The equation involved is :

Na₂CO₃ + 2HCl---> 2NaCl + CO₂ +H₂O

3) On passing through lime water white ppt formed :

When this gas that is carbon dioxide is passed it turns lime water milky due to formtaion of whit ppt of Calcium carbonate .

The reaction involved is :

CO₂ + Ca(OH)₂----> CaCO₃ + H₂O

        (slaked lime )   (calcium carbonate)

                                   white ppt .

The Z is identified as : CaCO₃