Question

A compound x2o3 contains 31.8 oxygen by mass. the atomic weight of x is

Answer 1

Let the atomic mass of 1 mol of element X is m g/mol.
Thus molar mass of compound = 2m + 16
×
3 = 2m+ 48 g/mol

Given that percentage of oxygen in the compound is 31.58%

Thus
percentage of oxygen in the compound =

Amount of oxygen in the compound/ molar mass of compound *100
31.58= 48/2m +48 *100

Mass of 1 mol X is 51.99 g.
Thus atomic mass of element X is 51.99 amu.

Answer 2

Answer:

In X2 O3,

Percentage of oxygen by weight = 31.58

Percentage of X by weight = 68.42

Let the atomic weight of X = x

2x/2x+48 × 100 = 68.42

∴ x = 51.99

So, atomic mass of X is 52 g mol-¹.

Explanation:

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