Question

a compresional wave of frequency 380cycles/sec is set up in iron rod and passes from iron rod into air.Speed of air is 5100m/s in iron and 330m/s in air.Find the wavelength of wave in iron and air​

Answer 1

Explanation:

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Given, frequency of wave(f) = 380 cycles/sec

= 380Hz

Speed of wave in Iron(v) = 5100m/s

•°•Speed,v =wavelength×frequency

==> Speed/frequency= Wavelength

==>5100/380 = Wavelength of wave in Iron rod

==> Wavelength of wave in Iron rod= 13.42m

But when wave changes medium, wavelength changes but frequency doesn't change.

==> Frequency remains 380 He

Now, speed of wave in Air= 330m/s

•°• Speed/Frequency= Wavelength of wave in air

==> 330/380= Wavelength of wave in air

==> Wavelength of wave in air= 0.87m

Thus wavelength of wave in iron rod and air is 13.42 m and 0.87 m respectively.

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Answer 2

Explanation:

use formula

wave velocity =frequency × wavelength

wavelength =v/n

plz remember

here frequency [n] is constant

so take same for both. put values and get your ans.