Computer Science, asked by soumyagampa99, 10 months ago

A computer employs RAM chips of 256 x 8 and ROM chips of
1024 x 8. The computer system needs 2K bytes of RAM, 4K bytes
of ROM, and four interface units, each with four registers. A
memory- mapped 1/0 configuration is used. The two highest-order
bits of the address bus are assigned 00 for RAM, 01 for ROM, and
10 for interface registers.




a) How many RAM and ROM chips are needed?
b) Draw a memory-address map for the system.
c) Give the address range in hexadecimal for RAM, ROM, and
interface

Answers

Answered by shridharjogin1998
0

Answer:

a

Explanation:

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