Question

A computer monitor is labelled as being 17 inches this distance is the diagonal distance across the screen if the screen measures 8 inches in height ,what is the actual width of the screen???​

Answer 1

Answer:

The Computer Screen Is Rectangular

Thus, It Is 90 Degrees At Each Edge.

Step-by-step explanation:

According To Pythagoras Threom:

${a}^{2} + {b}^{2} = {c}^{2}$

Given:

Diagonal Distance Is Hypotenuse

I.e. 17 Inchs

Height Distance Is Attitude

I.e. 8 Inchs

Thus,

${8 }^{2} + {b}^{2} = {17}^{2} \\ 64 + {b}^{2} = 289 \\289 - 64 = \sqrt{b} \\ 225 = \sqrt{b} \\ 15 = b$

Therefore, Width/Base Of The Screen Is 15 Inchs

Answer 2

Answer:

width of the computer screen is 15 CM.

Step-by-step explanation:

diagonal = H {hypotenuse}

height = P {perpendicular}

base = B {base}

given,

H = 17 CM

P = 8 CM

B = (?)

2 2 2

• H = B + P

2 2 2

17 = b + 8

2

289 = b + 64

2

b = 289 - 64

2

b = 225

2

b =

$\sqrt{225}$

• B = 15 inches

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