Math, asked by apacter1234, 7 months ago

A computer producing factory has only two plants T1 and T2. Plant T1 produces 20% and plant T2 produces 80% of the total computer produced. 7% of computers produced in the factory turn out to be defective. It is known that P(computer turns out to be defective given that it is produced in plant T1)=10P(computer turns out to be defective given that it is produced in plant T2), When P(E) denotes the probability of an event E. A computer produced in the factory is randomly selected and it does not turn out to be defective. Then the probability it is produced in plant T2 is____

Answers

Answered by saurabh363590
0

Answer:

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