Computer Science, asked by manishlodhe3283, 10 months ago

A computer supports one address and two address instructions. All the Addresses are the memory addresses. Memory size is 1Mbyte. How many one address instructions are possible if it has 240 two addresses instructions? (Assume binary instructions code has 48 bits)

Answers

Answered by BushrajavediqbalKhan
1

Explanation:

12 bit two address instruction will reserved 24 bit of instruction and remaining 8 bits will be used for opcode.

Total number of opcode that can be generated from 8 bit is 2^8 = 256.

Since 250 two address instruction has already used 250 possible opcode pattern then only 6 possible pattern is left to assign to one address instruction i.e 256 - 250 .

6 (possible opcode)*2^12(bits pattern possible due to one address instruction) = 24576.

Total one address instruction possible is 24576.

Answered by Anonymous
0

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