Question

A computer uses a memory unit with 512k words of 32 bits each. a binary instruction code is stored in one word of memory. the instruction has four parts: an indirect bit, an operation code, a register code part to specify one of 32 registers, and an address part.

a. how many bits are there in the operation code, the register code part and the address part?

b. draw the instruction word format and indicate the number of bits in each part.

c. how many bits are there in the data and address inputs of the memory?

Answer 1

Answer:

1,4,8,19

Explanation:

512 = 19 bits

256 = 8 bits

Indirect addressing bit = 1

19+8+1-32 = 4