A con came mirror produced as real image of
height 2cm of an object of height 0.5 cm placed 10cm away from the mirror Find the portion of the image and focal length of the mirror
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A con came mirror produced as real image of
height 2cm of an object of height 0.5 cm placed 10cm away from the mirror Find the portion of the image and focal length of the mirror
h = 0.5 cm
h’ = -2 cm
u = -10 cm
m = h’/h = -v/u
-2/0.5 = -v/-10
V = -40 cm
1/v + 1/u = 1/f
1/(-40) + 1/(=10) = 1/f
1/f = (-1 -4)/40
1/f = -5/40
F = -40/5
F = -8 cm
Hence the focal point will be -8 cm and the height real image of the object will be 40 cm.
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