Question

A concave lens focal length 15cm forms an image 10cm from the lens how far is the object placed from the lens find the magnification produced by lens with the help of this mention of nature of the image​

Answer 1

Explanation:

Focal length (f ) = -15 cm

Distance of image (v) = -10 cm

\(\frac{1}{v} – \frac{1}{u} = \frac{1}{f}\)

1/u = -(1/10) – (1/- 15)

1/u =1/15 – 1/10

1/u = -0.033

u = -30 cm

So, the object is placed 30 cm away from the concave lens.