Question

A concave lens forms the image of an object kept at a distance of 20cm in front of it at a distance of 10cm on the side of object fond the nature of image and the final length

Answer 1

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Answer 2

Getting the magnification:

(20cm)/(-10cm)=(img-obj)/(img-L)

=(img-L+L-obj)/(img-L)

=1-(obj-L)/(img-L)

= 1–1/M

-> M = 1/3

Getting the focal length/power

M=1-p(img-L)

1/3 = 1-p(-10cm)

p = -1/15cm

f = 1/p = -15cm