Question

A concave lens from real image 4 times magnifacied at a distance of 60cm from a lens calculate focal length and power​

Answer 1

Answer:

given :

magnification=m=-4[since it is real and magnified]

v= 60cm

object distance=u=?

magnification =m=V/u

u= 60/-4 =-15cm

Focal length=f=?

f=1/v - 1/u

=1/60 +1/15

=4+1/60

=5/60

f=60/5

=12cms

∴ Foal length of convex lens=12cm

Power=P=?

p=1/f (in m)

=100/f ( in cm)

=100/12

=+8.33 Diopters

∴ P=+8.3 D

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