a concave lens has a focal length of 10 cm where should the object be place to form a virtual image at a distance 30 cms from the lens
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Answer:
The object should be placed 7.5 cm from the lens.
Explanation:
Given: Focal length(f) = -10 cm
Image distance(v) = 30 cm
To find: Image distance(u)
Solution: By using lens formula = 1/f = 1/v - 1/u
So, 1/u = 1/v - 1/f
1/u = 1/30 - 1/-10
1/u = -1-3/-30
1/u = -4/30
u = -7.5 cm
So, The object should be placed 7.5 cm from the lens.
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