A concave lens has focal length of 20 cm. At what distance from the lens a 5 cm tall object be placed so that it forms an image at 15 cm from the lens? Also calculate the size of the image formed.
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Answer:
F--20
H¹-20 cm
v--15cm( convance lens from the virtual images)
Explanation:
1/v-1/ u-1/f
1/-15 -1/u =1/-20
1/u=-(1/15) +(1/20)
1/u--1/60
u=-60
object should be placed 60 cm to left of the lens
1/-u=1/60
u--60 cm
object should be placed 60 cm to the left of the lens
m=v/u -h2/5
h2 - 1.25 cm
image formed1. 25 cm high
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