Question

A concave lens of focal length 15 cm forms an image 10 cm from the lens. How far is the
object placed from the lens? Draw the ray diagram.​

Answer 1

Answer:

Focal length (f ) = -15 cm

Focal length (f ) = -15 cmDistance of image (v) = -10 cm

Focal length (f ) = -15 cmDistance of image (v) = -10 cm1v–1u=1f

Focal length (f ) = -15 cmDistance of image (v) = -10 cm1v–1u=1f1/u = -(1/10) – (1/- 15)

Focal length (f ) = -15 cmDistance of image (v) = -10 cm1v–1u=1f1/u = -(1/10) – (1/- 15)1/u =1/15 – 1/10

Focal length (f ) = -15 cmDistance of image (v) = -10 cm1v–1u=1f1/u = -(1/10) – (1/- 15)1/u =1/15 – 1/101/u = -0.033

Focal length (f ) = -15 cmDistance of image (v) = -10 cm1v–1u=1f1/u = -(1/10) – (1/- 15)1/u =1/15 – 1/101/u = -0.033u = -30 cm

Focal length (f ) = -15 cmDistance of image (v) = -10 cm1v–1u=1f1/u = -(1/10) – (1/- 15)1/u =1/15 – 1/101/u = -0.033u = -30 cmSo, the object is placed 30 cm away from the concave lens.

pls follow and mark me as brainalist