a concave lens of focal length 15cm forms an image 10cm the lens how far is the object placed from the lens? draw the ray diagram.
Answers
Answer:
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Explanation:
Focal length (f ) = -15 cm
length (f ) = -15 cmDistance of image (v) = -10 cm
length (f ) = -15 cmDistance of image (v) = -10 cm
length (f ) = -15 cmDistance of image (v) = -10 cm
length (f ) = -15 cmDistance of image (v) = -10 cm
length (f ) = -15 cmDistance of image (v) = -10 cm 1/u = -(1/10) – (1/- 15)
length (f ) = -15 cmDistance of image (v) = -10 cm 1/u = -(1/10) – (1/- 15)1/u =1/15 – 1/10
length (f ) = -15 cmDistance of image (v) = -10 cm 1/u = -(1/10) – (1/- 15)1/u =1/15 – 1/101/u = -0.033
length (f ) = -15 cmDistance of image (v) = -10 cm 1/u = -(1/10) – (1/- 15)1/u =1/15 – 1/101/u = -0.033u = -30 cm
length (f ) = -15 cmDistance of image (v) = -10 cm 1/u = -(1/10) – (1/- 15)1/u =1/15 – 1/101/u = -0.033u = -30 cmSo, the object is placed 30 cm away from the concave lens.