A concave lens of focal length 15cm forms an image of an object kept at distance of 10cm from the
lens. Find the position and nature of the image formed by it.
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Concave lens
F= -15cm
U= -10cm
Using lens formula,
1/v-1/u = 1/f
1/v+ 1/10= -1/15
1/v = -1/10-1/15
1/v = -3-2/30
1/v = -5/30
1/v = -1/6
Therefore, v = -6cm
Magnification = v/u
V/u = -6/-10
Therefore , m= 3/5
Therefore, the image formed is virtual, erect and diminished
F= -15cm
U= -10cm
Using lens formula,
1/v-1/u = 1/f
1/v+ 1/10= -1/15
1/v = -1/10-1/15
1/v = -3-2/30
1/v = -5/30
1/v = -1/6
Therefore, v = -6cm
Magnification = v/u
V/u = -6/-10
Therefore , m= 3/5
Therefore, the image formed is virtual, erect and diminished
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