a concave lens of focal length 16cm is used to form an image of object of length 9 cm is kept at a distance of 13 cm it use lens formula to determine nature position length of the image also draw ray diagram
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f= 60 cm
u= -30 cm
h=9 cm
nature=?, v=?, h of object=?,
using lens formula,
1/v+1/u=1/f
apply the values of U and F then you would get the value of V (position)
V= 20cm
for height of the image use,
m=v/u=h/h
you will get m= -2/3
now , m=h/h
height of image = - 6 cm
nature of the image formed is real and inverted,
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