Question

A concave lens of Focal length of 15cm Forms An image
10cm From the lens How far
is the object Placed from the lens?​

Answer 1

Answer:

Focal length (f ) = -15 cm

Distance of image (v) = -10 cm

\(\frac{1}{v} – \frac{1}{u} = \frac{1}{f}\)

1/u = -(1/10) – (1/- 15)

1/u =1/15 – 1/10

1/u = -0.033

u = -30 cm

so the object is placed 30 cm away from the concave lens.

Explanation:

Answer 2

ANSWER:-

GIVEN:-

f= -15

v= -10

From mirror formula,

$\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$

$\frac{1}{ - 10} - \frac{1}{u} = \frac{1}{ - 15}$

$\frac{1}{u} = \frac{1}{15} - \frac{1}{10}$

$\frac{1}{u} = \frac{1}{15} - \frac{1}{10}$

$u = - 30cm$

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