a concave lens of power 10d is placed in contact with convex lens of 2d what will be the nature of combined lens
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Answer:
Given,
P
1
=
f
1
1
=+10D
P
2
=
f
2
1
=−5D
M=2
The focal length of the combination,
f
1
=
f
2
1
+
f
2
1
f
1
=10−5=+5D
f=
5
100
=20cm
For virtual image, M=
u
v
v=2u
From lens formula
f
1
=
v
1
−
u
1
20
1
=
2u
1
−
u
1
20
1
=−
2u
1
u=−10cm
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