Question

A concave mirorr produces 10 cm long image of an object of height of 2cm.What is the magnification produced

Answer 1

Given ,

Image height (hi) = 10 cm

Object height (ho) = 2 cm

We know that , the magnification of mirror is given by

$\boxed{ \tt{Magnification \: \: (m) = \frac{ h_{i} }{h_{o} } }}$

Thus ,

m = 10/2

m = 5

$\therefore$ The size of image is 5 times of the size of object