a concave mirror focal length of 4cm and an object 2cm tall is placed 9cm away from it .
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1/v + 1/u = 1/f
1/v = 1/f - 1/u
= -1/4 - (-1/9)
= -1/4 + 1/9
= -9 + 4/36
= -5/36
v = 36/-5
= -7.2 cm
then,
m = -v/u
= -(-7.2)/-9
= -0.8
Again,
also,
m = h'/h
-0.8 = h'/2
h' = -1.6 cm
SIZE OF THE IMAGE IS 1.6 CM
Therefore:- the image is formed at a distance of 7.2 cm from the mirror.
that's all
Note:- RIGHT QUESTION PROPERLY
1/v = 1/f - 1/u
= -1/4 - (-1/9)
= -1/4 + 1/9
= -9 + 4/36
= -5/36
v = 36/-5
= -7.2 cm
then,
m = -v/u
= -(-7.2)/-9
= -0.8
Again,
also,
m = h'/h
-0.8 = h'/2
h' = -1.6 cm
SIZE OF THE IMAGE IS 1.6 CM
Therefore:- the image is formed at a distance of 7.2 cm from the mirror.
that's all
Note:- RIGHT QUESTION PROPERLY
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