Question

A concave mirror forms a real image of an object at a distance of 30 cm from the mirror, when it is kept at a distance of 50 cm from the mirror. Then find the magnification of mirror. *​

Answer 1

Answer:

- 90 is the Answer

Step-by-step explanation:

u=−30cm and magnification m=(−v/u)=−3 so v=(3u)

image is real so m should be negative v should be negative so v=−90cm

putting the above values of v and u in the Mirror equation,

f

1

=

u

1

+

v

1

we get focal length f=−22.5cm and image position v=−90......

mark me as brainliest please........

Answer 2

Answer:

Given:-

A real image is formed in the mirror, so it is concave mirror.. so the image distance, object distance and focal length all will be in minus values.

Let image distance be u = -30cm

Let object distance be v = -50cm

magnification of a mirror = image distance/object distance

i.e. -v/u = 50/-30 => -5/3

So the image formed is 5/3 times bigger than the size of the object.....

Shayad abhi sabke paper chal rahe hain ...... tabhi 10th waalon ke ques jyada hain..... mere bhee kyunki chal rahe hain, 'am in also 10th.....

ALL THE BEST FOR BOARDS.....

Hope you may got it

Please mark it as brainliest plzzzz and like it also

Please follow me don't forget it if you want to have good and unspamed answers

Thank you