A concave mirror forms a real image of an object placed in front of it at a distance
30cm, of size three times the size of the object. Find (a) focal length of the mirror
(b) position of image
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A.
u=−30cm,m=−3,
m=f−uf⇒−3=f−(−30)f=f+30f
⇒−3f−90=f
⇒−4f=90
→f=−490=−245=−22.5cm
B.
u1+v1=f1⇒−301+v1=2−45
v1=[301−452]⇒903−4=90−1
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