Question

a concave mirror forms a virtual and ercet image at a distance of 30cm from the mirror when the object is held at 10cm in front of the mirror. calculate focal length of the mirror​

Answer 1

Since the image is erect , so the magnification ratio must be positive .

m=2

also u=−10cm

so m=−

u

v

2=−

−10

v

v=20cm

So the image is virtual and 20 cm from mirror on the other side of the object.

Answer 2

Answer:

As the object is in front of the mirror it is real and for real object the magnified image formed by concave mirror can be inverted (i.e., real) or erect (i.e., virtual), so there are two possibilities.

(a) If the image is inverted (i.e., real)

m=ff−u⇒−3=−30−30−u⇒u=−40 cm

Object must be at a distance of 40 cm in frond of the mirror (in between C and F).

Step-by-step explanation:

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