A concave mirror forms an image of 20cmhigh object on a screen placed 5.0m away from the mirror. The height of the image is 50cm. Find the focal length of the mirror and the distance between the mirror and the object.
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Given :
ho=20cm
image distance= v= - 5m=- 500cm
hi= -50cm
u=?
magnification = m= -v/u= hi/ho
m= -50/20= -5/2
m=-v/u
u=- v /m
= - 500x 2/5
= - 200 cm = - 2m
Focal length=f?
from mirror equation :
1/f=1/v+1/u
= -1/5 - 1/2
1/f= -2-5/10
1/f= - 7/10
f= -10/7 = - 1.44 m
∴ Focal length = f= - 1.44m
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