A concave mirror has a focal length of 4cm and an object 2cm tall is placed 9cm away from it. Find the nature , position and size of the image formed.
Answers
Answered by
213
Hi !
focal length = f = - 4cm
height of object = + 2cm
object distance = u = - 9cm
image distance = v = ?
height of image = size = h' = ?
mirror formula,
1/v + 1/u = 1/f
1/v = 1/f - 1/u
= -1/4 - (-1/9)
= -1/4 + 1/9
= -9 + 4/36
= -5/36
v = 36/-5
= -7.2 cm
Hence,
the image is formed at a distance of 7.2 cm from the mirror.
Magnification = m
m = -v/u
= -(-7.2)/-9
= -0.8
As the magnification is negative , the image is real , inverted.
also,
m = h'/h
-0.8 = h'/2
h' = -1.6 cm
SIZE OF THE IMAGE IS 1.6 CM
focal length = f = - 4cm
height of object = + 2cm
object distance = u = - 9cm
image distance = v = ?
height of image = size = h' = ?
mirror formula,
1/v + 1/u = 1/f
1/v = 1/f - 1/u
= -1/4 - (-1/9)
= -1/4 + 1/9
= -9 + 4/36
= -5/36
v = 36/-5
= -7.2 cm
Hence,
the image is formed at a distance of 7.2 cm from the mirror.
Magnification = m
m = -v/u
= -(-7.2)/-9
= -0.8
As the magnification is negative , the image is real , inverted.
also,
m = h'/h
-0.8 = h'/2
h' = -1.6 cm
SIZE OF THE IMAGE IS 1.6 CM
Ravi1oth:
thank you very much
how can i edit it
u didnt ans , so how can u edit ?
u r welcome :)
ok
hey sry for my mistake but i m not able to edit the pic sry once again
its ok
☺☺
Answered by
82
hope it will help you
Attachments:
Similar questions