Question

A concave mirror having the focal length 15cm, forms an image having twice the linear dimensions of the object. If the image is virtual, then the position of the object will be
Ans: -7.5 cm plz give me solution

Answer 1

u = 7.5 cm
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Answer 2

Answer:

The position of the object is -7.5 cm.

Explanation:

Given that,

Focal length of concave mirror = -15 cm

Magnification = 2

We  need to calculate the position of the image

Using formula of magnification

$m =-\dfrac{v}{u}$

$2=-\dfrac{v}{u}$

$v = -2u$

We need to calculate the position of the object

Using formula of lens

$\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}$

Put the value into the formula

$\dfrac{1}{-2u}=\dfrac{1}{15}+\dfrac{1}{u}$

$\dfrac{1}{15}=\dfrac{1}{-2u}-\dfrac{1}{u}$

$\dfrac{1}{-15}=\dfrac{1}{2u}$

$2u=-15$

$u =-7.5\ cm$

Hence, The position of the object is -7.5 cm.