Question

A concave mirror of focal length
10 cm is kept in front of an object at a distance of
50 cm from it. If the object is 1.0 cm high, what
will be the size of the image?
​

Answer 1

Answer:

Given :

focal length = -10 cm

distance of the object (u) = 50cm

height of object( o) = 1cm

using the formula 1/f= 1/v +1/u

( for concave mirror );

1/10= 1/v + 1/u

1/10 = 1/v + 1/50

1/v = 1/50- 1/10

1/v = -2/25

v= -25/2

v= - 12.5cm

now using formula for magnification;

m= v/u =i/o

-12.5/ -50= i/1

12.5/50= i

i= 0.25cm

therefore the height of the image formed is o.25cm...

HOPE IT HELPS!!!!

Answer 2

Answer: -0.25 cm

Here, negative sign shows that image is real and inverted.