a concave mirror of focal length 15 cm forms an image of an object kept at a distance of 10 cm from the mirror.Find the position, nature and size of the image formed by it by drawing a ray diagram.
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given data
focal length=-15cm
object distance=-10cm
position of image =?
nature of image=?
size of the image =?
•.•mirror formula
1/f=1/ u + 1/v
1/-15=1/-10+1/v
1/-15+1/10 =1/ v
-2+3/30=1/v
1/30=1/v
1/30=1/v
v=30cm
since magnification
hi/ho=-v/u
= -30/-10
=3cm
hence position of image is 30cm,image is erect,enlarged,virtual
focal length=-15cm
object distance=-10cm
position of image =?
nature of image=?
size of the image =?
•.•mirror formula
1/f=1/ u + 1/v
1/-15=1/-10+1/v
1/-15+1/10 =1/ v
-2+3/30=1/v
1/30=1/v
1/30=1/v
v=30cm
since magnification
hi/ho=-v/u
= -30/-10
=3cm
hence position of image is 30cm,image is erect,enlarged,virtual
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