a concave mirror of focal length 15cm can form a magnified erect as well as inverted image of an object placed in front of it justify the statement stating the position of the object with respect to the power of the mirror in both the cases for obtaining the images
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Hey... I think this can be ur answer!!
(1) First case(magnified and erect image)
f=-15cm
The object should be placed between F and P to obtain magnified and erect image
P=100/f = 100/-15 = - 6.67 D
(2) second case (magnified and inverted image)
The object should be placed between C and F
P=-6.67D
(1) First case(magnified and erect image)
f=-15cm
The object should be placed between F and P to obtain magnified and erect image
P=100/f = 100/-15 = - 6.67 D
(2) second case (magnified and inverted image)
The object should be placed between C and F
P=-6.67D
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