A concave mirror of focal length 15cm forms an image having twice the linear dimension of the object.find the position of the object when the image is virtual.
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Focal length of concave mirror
f=−15 cm
magnification = 2 Linear magnification
υ=−2u
1f=1υ+1u
n=−7.5 cm
f=−15 cm
magnification = 2 Linear magnification
υ=−2u
1f=1υ+1u
n=−7.5 cm
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