A concave mirror of focal length 18 cm forms an erect image, three times the size of the object, how far is the object from the mirror?
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Answer:
12 cm
Step-by-step explanation:
Given there is a concave mirror.
Focal length, f = -18 cm
Also, it's given that, it forms an erect image, three times the size of object.
Therefore, it will be a virtual image.
Therefore, we will get,
Object distance, u = -ve
Image distance, v = +ve
Now, we have,
Magnification, m = 3
But, we know that,
m = -v/u
Therefore, we will get,
=> -v/u = 3
=> v = - 3u
=> v = - 3u
Now, we know the mirror formula, i.e.,
1/u + 1/v = 1/f
Substituting the values, we get,
=> 1/u - 1/3u = -1/18
=> 3/3u - 1/3u = -1/18
=> (3-1)/3u = -1/18
=> 2/3u = -1/18
=> 3u/2 = -18
=> 3u = -18 × 2
=> 3u = -36
=> u = -36/3
=> u = -12
Therefore, we have,
=> v = -3(-12)
=> v = 36
Hence, the object is at a distance of 12 cm from the mirror.
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