Physics, asked by srinivithag, 10 months ago

A concave mirror of focal length f (in air) is immersed in water (μ=4/3). The focal length of the mirror in water will be

Answers

Answered by ks298854

0

Explanation:

ANSWER

f1=(μwaμga−1)(R11−R21)

By substituting the values given in the above equation we get

f1=(341.5−1)(121+181)

=57.6cm

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