A concave mirror of focal length f (in air) is immersed in water (μ=4/3). The focal length of the mirror in water will be
Answers
Answered by
0
Explanation:
ANSWER
f1=(μwaμga−1)(R11−R21)
By substituting the values given in the above equation we get
f1=(341.5−1)(121+181)
=57.6cm
Similar questions