Physics, asked by mishrarajan282, 1 year ago

A concave mirror of focal length f produces an image n times the size of the object. If the image is real, then the distance of the object from the mirror is...... options:- a) (n+1)*f. b) (n-1)/n*f. c) (n-1)*f. d) (n+1)/n*f
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Answered by CarliReifsteck
75

Answer:

The distance of the object from the mirror is  \dfrac{n+1}{n}f

d is correct option.

Explanation:

Given that,

Focal length = f

We have given,

\dfrac{size\ of\ image}{size\ of\ object}=n

In case of a concave mirror , if the image is real then it must be inverted

So, The magnification is

m=-n=\dfrac{-v}{u}

m=n=\dfrac{v}{u}

Using mirror formula,

\dfrac{1}{u}+\dfrac{1}{v}=\dfrac{1}{f}

1+\dfrac{u}{v}=\dfrac{u}{f}

1+\dfrac{1}{n}=\dfrac{u}{f}

u = \dfrac{n+1}{n}f

Hence, The distance of the object from the mirror is  \dfrac{n+1}{n}f

Answered by amittiwari3721
14

Answer:

Explanation:

Here is it's answer,

Hope you will understand very easily.

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