Question

A concave mirror of focal length is 15cm makes a real image of object at a distance of 45cm find object distance and magnification

full solutions will get brainliest answers​

Answer 1

Answer:

given that

f= 15 cm

D= 45

Find = object distance and magnification

Explanation:

Focal length(f)= -15 cm, magnification= -3 (image is real). So, -v/u=-3 ; or v=3u {v=image distance and u=object distance}. Using mirror formula,

1/f= 1/v + 1/u

-1/15 = 1/3u + 1/u

4/3u = -1/15

u= -20 cm

v =3u= 3×(-20)= -60 cm

So object is 20 cm and image is 60 cm in front of the mirror.

Answer 2

Explanation:

1/F = 1/V + 1/U

M = (F-V)/F

SIGN CONVENTION

FOR REAL

focal length is negative ,image distance is negative.

M = (- 15 +45)/- 15

= - 2.

1/U = 1/V - 1/F

= 1/45 - 1/15

= (15- 45)/( 45 X 15)

= -30 /(45 X 15)

= -2 /45

U = -45/2

= - 22.5 cm