A concave mirror of focal length is 15cm makes a real image of object at a distance of 45cm find object distance and magnification
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Answered by
1
Answer:
given that
f= 15 cm
D= 45
Find = object distance and magnification
Explanation:
Focal length(f)= -15 cm, magnification= -3 (image is real). So, -v/u=-3 ; or v=3u {v=image distance and u=object distance}. Using mirror formula,
1/f= 1/v + 1/u
-1/15 = 1/3u + 1/u
4/3u = -1/15
u= -20 cm
v =3u= 3×(-20)= -60 cm
So object is 20 cm and image is 60 cm in front of the mirror.
Answered by
1
Explanation:
1/F = 1/V + 1/U
M = (F-V)/F
SIGN CONVENTION
FOR REAL
focal length is negative ,image distance is negative.
M = (- 15 +45)/- 15
= - 2.
1/U = 1/V - 1/F
= 1/45 - 1/15
= (15- 45)/( 45 X 15)
= -30 /(45 X 15)
= -2 /45
U = -45/2
= - 22.5 cm
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