A concave mirror of radius 30cm is placed in water,how does its focal length differ? a.Increases b. Decreases c. Becomes 0 d. remains same
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1
Answer:
remains constant because nothing will change
Answered by
0
Answer:
It is given that:
Radius of curvature of the concave mirror, R = 30 cm (it have negative sign)
To Find: Focal length "f" = ?
As we know that the focal length is half of the radius of curvature.
So
R = 2f
f = R / 2
f = 30 cm / 2 = 15 cm
Thus, the focal length in air and water differ by 15 cm.
Explanation:
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